المساعد الشخصي الرقمي

مشاهدة النسخة كاملة : أول طلب لي في منتدى ديزاد باتنة خاص بالمادة العلوم الفيزيائية و التكنولوجية وأتمنى دخول أساتذة المادة العلوم الفيزيائية و التكنولوجية



romaissa
11-04-2013, بتوقيت غرينيتش 04:13 AM
أرجووووووووووووووكم أريد الاجابة النموذج مقترحية لهذا الموضوع هذه صورة للموضوع لأنه لم ينسخ الرسومات
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صحيح أو خطأ مع التعليل:

ü طيف الضوء الصادر من جسم ساخن هو طيف يتسع نحو اللون الأحمر بزيادة درجة الحرارة.

ü شعاع ضوئي يجتاز موشور من الزجاج زاويته A=60° و قرينة انكساره n=1.62 ل يبرز من الموشور.

ü ليزر طبي يصدر إشعاعا طول موجته λ=10.6 μ m ينتمي الى المجال تحت الأحمر( IR )

التمرين الثاني

زجاج من نوع Flintبتميز بقرينة انكسار قيمتها :

nR=1.612من أجل إشعاع احمر

nJ=1.621 من أجل إشعاع أصفر زجاج هواء

nB=1.671 من أجل إشعاع أزق

1) ما هي سرعة كل إشعاع عند اجتيازه هذا الزجاج ؟

2) تسقط حزمة ضوئية على سطح الزجاج بزاوية ورود 61.5°

_احسب زاوية انكسار كل شعاع

_ارسم الإشعاعات المنكسرة بدقة

_احسب زاوية انحراف كل شعاع.ماذا تلاحظ؟

_ارسم و حدد بالتقريب اتجاه الشعاع الأخضر

التمرين الثالث

ABCD مربع طول ضلعه a=2 cm توضع في رؤوسه الشحنات qD , qc , qB , qA, . A B

1_مثل القوى المتبادلة بين qA و بقية الشحنات.

2_احسب قيمة القوة الناتجة عن تأثير الشحنات qB , qAqD , في الشحنة , qc

اذا =10-6c/2qD =qc =qB =qA

D C

التمرين الرابع

1) نفاعل حجم V(L) من غاز ثنائي الأكسيجين O2لاحتراق 6.35 g من معدن النحاسCu

فيتشكل مسحوق اسود من أكسيد النحاس CuO.

_أكتب معادلة التفاعل الحادث

_أنشئ جدول تقدم التفاعل

_ارسم المنحنى البياني nCu=f(x)

2)إذا علمت أن من أجل x=0.005 mole يكون حجم ثنائي الأكسيجين المتبقي 0.12L :

_احسب حجم الغاز O2 المن التعليم الابتدائي

_استنتج المتفاعل المحد

_أعط الحصيلة النهائية للتفاعل Cu=63.5 g/mole Vm=24 L/mole

التمرين الخامس

كلور الكالسيوم Ca Cl2 ينحل في الماء معطيا شوارد الكلور Cl- و شوارد الكالسيوم Ca2+ .نذيب كتلة m منه في

1L من الماء و نأخذ100 mL فنجد كمية مادة لشوارد الكلور nCl-=0.02 mole :

1)أكتب معدلة انحلال كلور الكالسيوم في الماء

2)ما هو التركيز المولي للمحلول بشوارد Cl- وCa2+

3)ما هو التركيز المولي للمحلول C ؟استنتج الكتلة m لكلور الكالسيوم المذابة في الماء .
Ca=40 g/mole Cl=35.5 g/mole



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